(6x^3-5x-38)/(x-2)

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Solution for (6x^3-5x-38)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(6*x^3-(5*x)-38)/(x-2) = 0

(6*x^3-5*x-38)/(x-2) = 0

6*x^3-5*x-38 = 0

6*x^3-5*x-38 = 0

{ 1, -1, 2, -2, 19, -19, 38, -38 }

1

x = 1

6*x^3-5*x-38 = -37

1

-1

x = -1

6*x^3-5*x-38 = -39

-1

2

x = 2

6*x^3-5*x-38 = 0

2

x-2

6*x^2+12*x+19

6*x^3-5*x-38

x-2

12*x^2-6*x^3

12*x^2-5*x-38

24*x-12*x^2

19*x-38

38-19*x

0

6*x^2+12*x+19 = 0

DELTA = 12^2-(4*6*19)

DELTA = -312

DELTA < 0

x in { 2} 

x-2 = 0

1 = 0

x belongs to the empty set

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